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9x^2-78x+25=0
a = 9; b = -78; c = +25;
Δ = b2-4ac
Δ = -782-4·9·25
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-78)-72}{2*9}=\frac{6}{18} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-78)+72}{2*9}=\frac{150}{18} =8+1/3 $
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